(x+1)(2x-1)=(x+3)(2x-3)-14

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Solution for (x+1)(2x-1)=(x+3)(2x-3)-14 equation: 



(x+1)(2x-1)=(x+3)(2x-3)-14

We move all terms to the left:

(x+1)(2x-1)-((x+3)(2x-3)-14)=0

We multiply parentheses ..

(+2x^2-1x+2x-1)-((x+3)(2x-3)-14)=0



We calculate terms in parentheses: -((x+3)(2x-3)-14), so:

(x+3)(2x-3)-14

We multiply parentheses ..

(+2x^2-3x+6x-9)-14

We get rid of parentheses

2x^2-3x+6x-9-14

We add all the numbers together, and all the variables

2x^2+3x-23

Back to the equation:

-(2x^2+3x-23)



We get rid of parentheses

2x^2-2x^2-1x+2x-3x-1+23=0

We add all the numbers together, and all the variables

-2x+22=0

We move all terms containing x to the left, all other terms to the right

-2x=-22

x=-22/-2

x=+11

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