8z-33=3(3z-11)-z

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Solution for 8z-33=3(3z-11)-z equation: 



8z-33=3(3z-11)-z

We move all terms to the left:

8z-33-(3(3z-11)-z)=0



We calculate terms in parentheses: -(3(3z-11)-z), so:

3(3z-11)-z

We add all the numbers together, and all the variables

-1z+3(3z-11)

We multiply parentheses

-1z+9z-33

We add all the numbers together, and all the variables

8z-33

Back to the equation:

-(8z-33)



We get rid of parentheses

8z-8z+33-33=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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