4y-2(X-3)=12

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Solution for 4y-2(X-3)=12 equation: 



4y-2(y-3)=12

We move all terms to the left:

4y-2(y-3)-(12)=0

We multiply parentheses

4y-2y+6-12=0

We add all the numbers together, and all the variables

2y-6=0

We move all terms containing y to the left, all other terms to the right

2y=6

y=6/2

y=3

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