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1/2x+12x=5
We move all terms to the left:
1/2x+12x-(5)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
12x+1/2x-5=0
We multiply all the terms by the denominator
12x*2x-5*2x+1=0
Wy multiply elements
24x^2-10x+1=0
a = 24; b = -10; c = +1;
Δ = b2-4ac
Δ = -102-4·24·1
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2}{2*24}=\frac{8}{48} =1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2}{2*24}=\frac{12}{48} =1/4 $
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