8y2-13y+5=0

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Solution for 8y2-13y+5=0 equation: 



8y^2-13y+5=0

a = 8; b = -13; c = +5;
Δ = b2-4ac
Δ = -132-4·8·5
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-3}{2*8}=\frac{10}{16}
=5/8
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+3}{2*8}=\frac{16}{16}
=1
$

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