(12+3x)*0,33=7(2-x)-2

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Solution for (12+3x)*0,33=7(2-x)-2 equation: 



(12+3x)*0.33=7(2-x)-2

We move all terms to the left:

(12+3x)*0.33-(7(2-x)-2)=0

We add all the numbers together, and all the variables

(3x+12)*0.33-(7(-1x+2)-2)=0

We multiply parentheses

0.99x-(7(-1x+2)-2)+3.96=0



We calculate terms in parentheses: -(7(-1x+2)-2), so:

7(-1x+2)-2

We multiply parentheses

-7x+14-2

We add all the numbers together, and all the variables

-7x+12

Back to the equation:

-(-7x+12)



We get rid of parentheses

0.99x+7x-12+3.96=0

We add all the numbers together, and all the variables

7.99x-8.04=0

We move all terms containing x to the left, all other terms to the right

7.99x=8.04

x=8.04/7.99

x=1+0.05/7.99

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