8y2+40y+50=0

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Solution for 8y2+40y+50=0 equation: 



8y^2+40y+50=0

a = 8; b = 40; c = +50;
Δ = b2-4ac
Δ = 402-4·8·50
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{-40}{16}=-2+1/2$

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