-10(1+4b)+12=6(-7b-8+6

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Solution for -10(1+4b)+12=6(-7b-8+6 equation: 



-10(1+4b)+12=6(-7b-8+6

We move all terms to the left:

-10(1+4b)+12-(6(-7b-8+6)=0

We add all the numbers together, and all the variables

-10(4b+1)-(6(-7b-2)+12=0

We multiply parentheses

-40b-(6(-7b-2)+12-10=0

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