8y-8+2(4y+5)=-2(y+5)

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Solution for 8y-8+2(4y+5)=-2(y+5) equation: 



8y-8+2(4y+5)=-2(y+5)

We move all terms to the left:

8y-8+2(4y+5)-(-2(y+5))=0

We multiply parentheses

8y+8y-(-2(y+5))+10-8=0



We calculate terms in parentheses: -(-2(y+5)), so:

-2(y+5)

We multiply parentheses

-2y-10

Back to the equation:

-(-2y-10)



We add all the numbers together, and all the variables

16y-(-2y-10)+2=0

We get rid of parentheses

16y+2y+10+2=0

We add all the numbers together, and all the variables

18y+12=0

We move all terms containing y to the left, all other terms to the right

18y=-12

y=-12/18

y=-2/3

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