2(3c+8)=2c+16+4c

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Solution for 2(3c+8)=2c+16+4c equation: 



2(3c+8)=2c+16+4c

We move all terms to the left:

2(3c+8)-(2c+16+4c)=0

We add all the numbers together, and all the variables

2(3c+8)-(6c+16)=0

We multiply parentheses

6c-(6c+16)+16=0

We get rid of parentheses

6c-6c-16+16=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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