8y-32=4(y+2)

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Solution for 8y-32=4(y+2) equation: 



8y-32=4(y+2)

We move all terms to the left:

8y-32-(4(y+2))=0



We calculate terms in parentheses: -(4(y+2)), so:

4(y+2)

We multiply parentheses

4y+8

Back to the equation:

-(4y+8)



We get rid of parentheses

8y-4y-8-32=0

We add all the numbers together, and all the variables

4y-40=0

We move all terms containing y to the left, all other terms to the right

4y=40

y=40/4

y=10

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