-4(3y-2)+2y=2(y+9)

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Solution for -4(3y-2)+2y=2(y+9) equation: 



-4(3y-2)+2y=2(y+9)

We move all terms to the left:

-4(3y-2)+2y-(2(y+9))=0

We add all the numbers together, and all the variables

2y-4(3y-2)-(2(y+9))=0

We multiply parentheses

2y-12y-(2(y+9))+8=0



We calculate terms in parentheses: -(2(y+9)), so:

2(y+9)

We multiply parentheses

2y+18

Back to the equation:

-(2y+18)



We add all the numbers together, and all the variables

-10y-(2y+18)+8=0

We get rid of parentheses

-10y-2y-18+8=0

We add all the numbers together, and all the variables

-12y-10=0

We move all terms containing y to the left, all other terms to the right

-12y=10

y=10/-12

y=-5/6

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