8y-3/3y=2

Solution for 8y-3/3y=2 equation:

8y-3/3y=2

We move all terms to the left:

8y-3/3y-(2)=0


Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R


We multiply all the terms by the denominator


8y*3y-2*3y-3=0

Wy multiply elements

24y^2-6y-3=0

a = 24; b = -6; c = -3;
Δ = b2-4ac
Δ = -62-4·24·(-3)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-18}{2*24}=\frac{-12}{48}
=-1/4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+18}{2*24}=\frac{24}{48}
=1/2
$