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3x+4=2(x+3)+10
We move all terms to the left:
3x+4-(2(x+3)+10)=0
We calculate terms in parentheses: -(2(x+3)+10), so:We get rid of parentheses
2(x+3)+10
We multiply parentheses
2x+6+10
We add all the numbers together, and all the variables
2x+16
Back to the equation:
-(2x+16)
3x-2x-16+4=0
We add all the numbers together, and all the variables
x-12=0
We move all terms containing x to the left, all other terms to the right
x=12
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