8y-3(10-2y)-6+10y=6

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Solution for 8y-3(10-2y)-6+10y=6 equation: 



8y-3(10-2y)-6+10y=6

We move all terms to the left:

8y-3(10-2y)-6+10y-(6)=0

We add all the numbers together, and all the variables

8y-3(-2y+10)+10y-6-6=0

We add all the numbers together, and all the variables

18y-3(-2y+10)-12=0

We multiply parentheses

18y+6y-30-12=0

We add all the numbers together, and all the variables

24y-42=0

We move all terms containing y to the left, all other terms to the right

24y=42

y=42/24

y=1+3/4

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