12x2+24x-1440=0

Solution for 12x2+24x-1440=0 equation:

12x^2+24x-1440=0

a = 12; b = 24; c = -1440;
Δ = b2-4ac
Δ = 242-4·12·(-1440)
Δ = 69696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{69696}=264$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-264}{2*12}=\frac{-288}{24}
=-12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+264}{2*12}=\frac{240}{24}
=10
$