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8y(-5y-15)=36
We move all terms to the left:
8y(-5y-15)-(36)=0
We multiply parentheses
-40y^2-120y-36=0
a = -40; b = -120; c = -36;
Δ = b2-4ac
Δ = -1202-4·(-40)·(-36)
Δ = 8640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8640}=\sqrt{576*15}=\sqrt{576}*\sqrt{15}=24\sqrt{15}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-24\sqrt{15}}{2*-40}=\frac{120-24\sqrt{15}}{-80} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+24\sqrt{15}}{2*-40}=\frac{120+24\sqrt{15}}{-80} $
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