8(3-b)=2(5b+1)

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Solution for 8(3-b)=2(5b+1) equation: 



8(3-b)=2(5b+1)

We move all terms to the left:

8(3-b)-(2(5b+1))=0

We add all the numbers together, and all the variables

8(-1b+3)-(2(5b+1))=0

We multiply parentheses

-8b-(2(5b+1))+24=0



We calculate terms in parentheses: -(2(5b+1)), so:

2(5b+1)

We multiply parentheses

10b+2

Back to the equation:

-(10b+2)



We get rid of parentheses

-8b-10b-2+24=0

We add all the numbers together, and all the variables

-18b+22=0

We move all terms containing b to the left, all other terms to the right

-18b=-22

b=-22/-18

b=1+2/9

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