8x=(3x+10)(4x+10)

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Solution for 8x=(3x+10)(4x+10) equation: 



8x=(3x+10)(4x+10)

We move all terms to the left:

8x-((3x+10)(4x+10))=0

We multiply parentheses ..

-((+12x^2+30x+40x+100))+8x=0



We calculate terms in parentheses: -((+12x^2+30x+40x+100)), so:

(+12x^2+30x+40x+100)

We get rid of parentheses

12x^2+30x+40x+100

We add all the numbers together, and all the variables

12x^2+70x+100

Back to the equation:

-(12x^2+70x+100)



We add all the numbers together, and all the variables

8x-(12x^2+70x+100)=0

We get rid of parentheses

-12x^2+8x-70x-100=0

We add all the numbers together, and all the variables

-12x^2-62x-100=0

a = -12; b = -62; c = -100;
Δ = b2-4ac
Δ = -622-4·(-12)·(-100)
Δ = -956
Delta is less than zero, so there is no solution for the equation

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