5(3x+1)=9-2(x-7)

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Solution for 5(3x+1)=9-2(x-7) equation: 



5(3x+1)=9-2(x-7)

We move all terms to the left:

5(3x+1)-(9-2(x-7))=0

We multiply parentheses

15x-(9-2(x-7))+5=0



We calculate terms in parentheses: -(9-2(x-7)), so:

9-2(x-7)

determiningTheFunctionDomain
-2(x-7)+9

We multiply parentheses

-2x+14+9

We add all the numbers together, and all the variables

-2x+23

Back to the equation:

-(-2x+23)



We get rid of parentheses

15x+2x-23+5=0

We add all the numbers together, and all the variables

17x-18=0

We move all terms containing x to the left, all other terms to the right

17x=18

x=18/17

x=1+1/17

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