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8x^2=2x+15
We move all terms to the left:
8x^2-(2x+15)=0
We get rid of parentheses
8x^2-2x-15=0
a = 8; b = -2; c = -15;
Δ = b2-4ac
Δ = -22-4·8·(-15)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-22}{2*8}=\frac{-20}{16} =-1+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+22}{2*8}=\frac{24}{16} =1+1/2 $
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