2(3m-4)+3(2m-3)=-2(m+5)

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Solution for 2(3m-4)+3(2m-3)=-2(m+5) equation: 



2(3m-4)+3(2m-3)=-2(m+5)

We move all terms to the left:

2(3m-4)+3(2m-3)-(-2(m+5))=0

We multiply parentheses

6m+6m-(-2(m+5))-8-9=0



We calculate terms in parentheses: -(-2(m+5)), so:

-2(m+5)

We multiply parentheses

-2m-10

Back to the equation:

-(-2m-10)



We add all the numbers together, and all the variables

12m-(-2m-10)-17=0

We get rid of parentheses

12m+2m+10-17=0

We add all the numbers together, and all the variables

14m-7=0

We move all terms containing m to the left, all other terms to the right

14m=7

m=7/14

m=1/2

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