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8x^2-8.8x+2.1=0
a = 8; b = -8.8; c = +2.1;
Δ = b2-4ac
Δ = -8.82-4·8·2.1
Δ = 10.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8.8)-\sqrt{10.24}}{2*8}=\frac{8.8-\sqrt{10.24}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8.8)+\sqrt{10.24}}{2*8}=\frac{8.8+\sqrt{10.24}}{16} $
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