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6x^2-12.5x+6=0
a = 6; b = -12.5; c = +6;
Δ = b2-4ac
Δ = -12.52-4·6·6
Δ = 12.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12.5)-\sqrt{12.25}}{2*6}=\frac{12.5-\sqrt{12.25}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12.5)+\sqrt{12.25}}{2*6}=\frac{12.5+\sqrt{12.25}}{12} $
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