8x2-4x-4=0

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Solution for 8x2-4x-4=0 equation: 



8x^2-4x-4=0

a = 8; b = -4; c = -4;
Δ = b2-4ac
Δ = -42-4·8·(-4)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-12}{2*8}=\frac{-8}{16}
=-1/2
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+12}{2*8}=\frac{16}{16}
=1
$

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