21x-19=4(5x+5)-1

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Solution for 21x-19=4(5x+5)-1 equation: 



21x-19=4(5x+5)-1

We move all terms to the left:

21x-19-(4(5x+5)-1)=0



We calculate terms in parentheses: -(4(5x+5)-1), so:

4(5x+5)-1

We multiply parentheses

20x+20-1

We add all the numbers together, and all the variables

20x+19

Back to the equation:

-(20x+19)



We get rid of parentheses

21x-20x-19-19=0

We add all the numbers together, and all the variables

x-38=0

We move all terms containing x to the left, all other terms to the right

x=38

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