(2a+28)=(4a-4)

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Solution for (2a+28)=(4a-4) equation: 



(2a+28)=(4a-4)

We move all terms to the left:

(2a+28)-((4a-4))=0

We get rid of parentheses

2a-((4a-4))+28=0



We calculate terms in parentheses: -((4a-4)), so:

(4a-4)

We get rid of parentheses

4a-4

Back to the equation:

-(4a-4)



We get rid of parentheses

2a-4a+4+28=0

We add all the numbers together, and all the variables

-2a+32=0

We move all terms containing a to the left, all other terms to the right

-2a=-32

a=-32/-2

a=+16

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