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8x^2-13x-11=x2+3x+4
We move all terms to the left:
8x^2-13x-11-(x2+3x+4)=0
We add all the numbers together, and all the variables
8x^2-(+x^2+3x+4)-13x-11=0
We get rid of parentheses
8x^2-x^2-3x-13x-4-11=0
We add all the numbers together, and all the variables
7x^2-16x-15=0
a = 7; b = -16; c = -15;
Δ = b2-4ac
Δ = -162-4·7·(-15)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-26}{2*7}=\frac{-10}{14} =-5/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+26}{2*7}=\frac{42}{14} =3 $
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