4(3b+2)+1(4b+3)=5

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Solution for 4(3b+2)+1(4b+3)=5 equation: 



4(3b+2)+1(4b+3)=5

We move all terms to the left:

4(3b+2)+1(4b+3)-(5)=0

We multiply parentheses

12b+1(4b+3)+8-5=0

We add all the numbers together, and all the variables

12b+1(4b+3)+3=0

We move all terms containing b to the left, all other terms to the right

12b+1(4b+3)=-3

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