8x/6x=4/3x

Solution for 8x/6x=4/3x equation:

8x/6x=4/3x

We move all terms to the left:

8x/6x-(4/3x)=0


Domain of the equation: 6x!=0

x!=0/6

x!=0

x∈R



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

8x/6x-(+4/3x)=0

We get rid of parentheses

8x/6x-4/3x=0

We calculate fractions


24x^2/18x^2+(-24x)/18x^2=0

We multiply all the terms by the denominator


24x^2+(-24x)=0

We get rid of parentheses

24x^2-24x=0

a = 24; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·24·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*24}=\frac{0}{48}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*24}=\frac{48}{48}
=1
$