(7x-19)=(2x+4)+(2x+16)=180

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Solution for (7x-19)=(2x+4)+(2x+16)=180 equation: 



(7x-19)=(2x+4)+(2x+16)=180

We move all terms to the left:

(7x-19)-((2x+4)+(2x+16))=0

We get rid of parentheses

7x-((2x+4)+(2x+16))-19=0



We calculate terms in parentheses: -((2x+4)+(2x+16)), so:

(2x+4)+(2x+16)

We get rid of parentheses

2x+2x+4+16

We add all the numbers together, and all the variables

4x+20

Back to the equation:

-(4x+20)



We get rid of parentheses

7x-4x-20-19=0

We add all the numbers together, and all the variables

3x-39=0

We move all terms containing x to the left, all other terms to the right

3x=39

x=39/3

x=13

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