8x-7=5(10-x)+3(x+1)

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Solution for 8x-7=5(10-x)+3(x+1) equation: 



8x-7=5(10-x)+3(x+1)

We move all terms to the left:

8x-7-(5(10-x)+3(x+1))=0

We add all the numbers together, and all the variables

8x-(5(-1x+10)+3(x+1))-7=0



We calculate terms in parentheses: -(5(-1x+10)+3(x+1)), so:

5(-1x+10)+3(x+1)

We multiply parentheses

-5x+3x+50+3

We add all the numbers together, and all the variables

-2x+53

Back to the equation:

-(-2x+53)



We get rid of parentheses

8x+2x-53-7=0

We add all the numbers together, and all the variables

10x-60=0

We move all terms containing x to the left, all other terms to the right

10x=60

x=60/10

x=6

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