8x-7(3x-5)=2x-5(x+1)

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Solution for 8x-7(3x-5)=2x-5(x+1) equation: 



8x-7(3x-5)=2x-5(x+1)

We move all terms to the left:

8x-7(3x-5)-(2x-5(x+1))=0

We multiply parentheses

8x-21x-(2x-5(x+1))+35=0



We calculate terms in parentheses: -(2x-5(x+1)), so:

2x-5(x+1)

We multiply parentheses

2x-5x-5

We add all the numbers together, and all the variables

-3x-5

Back to the equation:

-(-3x-5)



We add all the numbers together, and all the variables

-13x-(-3x-5)+35=0

We get rid of parentheses

-13x+3x+5+35=0

We add all the numbers together, and all the variables

-10x+40=0

We move all terms containing x to the left, all other terms to the right

-10x=-40

x=-40/-10

x=+4

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