8x-5=2(3x+1)=2

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Solution for 8x-5=2(3x+1)=2 equation: 



8x-5=2(3x+1)=2

We move all terms to the left:

8x-5-(2(3x+1))=0



We calculate terms in parentheses: -(2(3x+1)), so:

2(3x+1)

We multiply parentheses

6x+2

Back to the equation:

-(6x+2)



We get rid of parentheses

8x-6x-2-5=0

We add all the numbers together, and all the variables

2x-7=0

We move all terms containing x to the left, all other terms to the right

2x=7

x=7/2

x=3+1/2

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