3(7r-6)+8=16+8r

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Solution for 3(7r-6)+8=16+8r equation: 



3(7r-6)+8=16+8r

We move all terms to the left:

3(7r-6)+8-(16+8r)=0

We add all the numbers together, and all the variables

3(7r-6)-(8r+16)+8=0

We multiply parentheses

21r-(8r+16)-18+8=0

We get rid of parentheses

21r-8r-16-18+8=0

We add all the numbers together, and all the variables

13r-26=0

We move all terms containing r to the left, all other terms to the right

13r=26

r=26/13

r=2

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