8x-4/7x=3

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Solution for 8x-4/7x=3 equation: 



8x-4/7x=3

We move all terms to the left:

8x-4/7x-(3)=0



Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



We multiply all the terms by the denominator


8x*7x-3*7x-4=0

Wy multiply elements

56x^2-21x-4=0

a = 56; b = -21; c = -4;
Δ = b2-4ac
Δ = -212-4·56·(-4)
Δ = 1337
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{1337}}{2*56}=\frac{21-\sqrt{1337}}{112}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{1337}}{2*56}=\frac{21+\sqrt{1337}}{112}
$

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