(6x+1)=2(9x-23)

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Solution for (6x+1)=2(9x-23) equation: 



(6x+1)=2(9x-23)

We move all terms to the left:

(6x+1)-(2(9x-23))=0

We get rid of parentheses

6x-(2(9x-23))+1=0



We calculate terms in parentheses: -(2(9x-23)), so:

2(9x-23)

We multiply parentheses

18x-46

Back to the equation:

-(18x-46)



We get rid of parentheses

6x-18x+46+1=0

We add all the numbers together, and all the variables

-12x+47=0

We move all terms containing x to the left, all other terms to the right

-12x=-47

x=-47/-12

x=3+11/12

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