8x-4(4x-3)=4(6x+4)-4

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Solution for 8x-4(4x-3)=4(6x+4)-4 equation: 



8x-4(4x-3)=4(6x+4)-4

We move all terms to the left:

8x-4(4x-3)-(4(6x+4)-4)=0

We multiply parentheses

8x-16x-(4(6x+4)-4)+12=0



We calculate terms in parentheses: -(4(6x+4)-4), so:

4(6x+4)-4

We multiply parentheses

24x+16-4

We add all the numbers together, and all the variables

24x+12

Back to the equation:

-(24x+12)



We add all the numbers together, and all the variables

-8x-(24x+12)+12=0

We get rid of parentheses

-8x-24x-12+12=0

We add all the numbers together, and all the variables

-32x=0

x=0/-32

x=0

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