8x-2(x-5)=3(2x+1)-1

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Solution for 8x-2(x-5)=3(2x+1)-1 equation: 



8x-2(x-5)=3(2x+1)-1

We move all terms to the left:

8x-2(x-5)-(3(2x+1)-1)=0

We multiply parentheses

8x-2x-(3(2x+1)-1)+10=0



We calculate terms in parentheses: -(3(2x+1)-1), so:

3(2x+1)-1

We multiply parentheses

6x+3-1

We add all the numbers together, and all the variables

6x+2

Back to the equation:

-(6x+2)



We add all the numbers together, and all the variables

6x-(6x+2)+10=0

We get rid of parentheses

6x-6x-2+10=0

We add all the numbers together, and all the variables

8!=0

There is no solution for this equation

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