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6x+12=2(x-3)+2(2x+2)
We move all terms to the left:
6x+12-(2(x-3)+2(2x+2))=0
We calculate terms in parentheses: -(2(x-3)+2(2x+2)), so:We get rid of parentheses
2(x-3)+2(2x+2)
We multiply parentheses
2x+4x-6+4
We add all the numbers together, and all the variables
6x-2
Back to the equation:
-(6x-2)
6x-6x+2+12=0
We add all the numbers together, and all the variables
14!=0
There is no solution for this equation
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