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8x-((x+3)-(2x+5))=12
We move all terms to the left:
8x-((x+3)-(2x+5))-(12)=0
We calculate terms in parentheses: -((x+3)-(2x+5)), so:We get rid of parentheses
(x+3)-(2x+5)
We get rid of parentheses
x-2x+3-5
We add all the numbers together, and all the variables
-1x-2
Back to the equation:
-(-1x-2)
8x+1x+2-12=0
We add all the numbers together, and all the variables
9x-10=0
We move all terms containing x to the left, all other terms to the right
9x=10
x=10/9
x=1+1/9
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