8x-(2x+4)=-(-5x+(-(-3x-1)))

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Solution for 8x-(2x+4)=-(-5x+(-(-3x-1))) equation: 



8x-(2x+4)=-(-5x+(-(-3x-1)))

We move all terms to the left:

8x-(2x+4)-(-(-5x+(-(-3x-1))))=0

We get rid of parentheses

8x-2x-(-(-5x+(-(-3x-1))))-4=0



We calculate terms in parentheses: -(-(-5x+(-(-3x-1)))), so:

-(-5x+(-(-3x-1)))



We calculate terms in parentheses: -(-5x+(-(-3x-1))), so:

-5x+(-(-3x-1))



We calculate terms in parentheses: +(-(-3x-1)), so:

-(-3x-1)

We get rid of parentheses

3x+1

Back to the equation:

+(3x+1)



We get rid of parentheses

-5x+3x+1

We add all the numbers together, and all the variables

-2x+1

Back to the equation:

-(-2x+1)



We get rid of parentheses

2x-1

Back to the equation:

-(2x-1)



We add all the numbers together, and all the variables

6x-(2x-1)-4=0

We get rid of parentheses

6x-2x+1-4=0

We add all the numbers together, and all the variables

4x-3=0

We move all terms containing x to the left, all other terms to the right

4x=3

x=3/4

x=3/4

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