8x+x2+10-38=180

Solution for 8x+x2+10-38=180 equation:

8x+x2+10-38=180

We move all terms to the left:

8x+x2+10-38-(180)=0

We add all the numbers together, and all the variables

x^2+8x-208=0

a = 1; b = 8; c = -208;
Δ = b2-4ac
Δ = 82-4·1·(-208)
Δ = 896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{896}=\sqrt{64*14}=\sqrt{64}*\sqrt{14}=8\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{14}}{2*1}=\frac{-8-8\sqrt{14}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{14}}{2*1}=\frac{-8+8\sqrt{14}}{2}
$