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(2x+1)=(7x+1)
We move all terms to the left:
(2x+1)-((7x+1))=0
We get rid of parentheses
2x-((7x+1))+1=0
We calculate terms in parentheses: -((7x+1)), so:We get rid of parentheses
(7x+1)
We get rid of parentheses
7x+1
Back to the equation:
-(7x+1)
2x-7x-1+1=0
We add all the numbers together, and all the variables
-5x=0
x=0/-5
x=0
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