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4(3x*1)=3(2x-3)
We move all terms to the left:
4(3x*1)-(3(2x-3))=0
We add all the numbers together, and all the variables
4(+3x*1)-(3(2x-3))=0
We multiply parentheses
12x-(3(2x-3))=0
We calculate terms in parentheses: -(3(2x-3)), so:We get rid of parentheses
3(2x-3)
We multiply parentheses
6x-9
Back to the equation:
-(6x-9)
12x-6x+9=0
We add all the numbers together, and all the variables
6x+9=0
We move all terms containing x to the left, all other terms to the right
6x=-9
x=-9/6
x=-1+1/2
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