(5z+1)/(3z-1)=3/2

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Solution for (5z+1)/(3z-1)=3/2 equation: 



(5z+1)/(3z-1)=3/2

We move all terms to the left:

(5z+1)/(3z-1)-(3/2)=0



Domain of the equation: (3z-1)!=0

We move all terms containing z to the left, all other terms to the right

3z!=1

z!=1/3

z!=1/3

z∈R



We add all the numbers together, and all the variables

(5z+1)/(3z-1)-(+3/2)=0

We get rid of parentheses

(5z+1)/(3z-1)-3/2=0

We calculate fractions


(10z+2)/(6z-2)+(-9z+3)/(6z-2)=0

We multiply all the terms by the denominator


(10z+2)+(-9z+3)=0

We get rid of parentheses

10z-9z+2+3=0

We add all the numbers together, and all the variables

z+5=0

We move all terms containing z to the left, all other terms to the right

z=-5

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