8x+5(4x-3)=4(6x+4)-3

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Solution for 8x+5(4x-3)=4(6x+4)-3 equation: 



8x+5(4x-3)=4(6x+4)-3

We move all terms to the left:

8x+5(4x-3)-(4(6x+4)-3)=0

We multiply parentheses

8x+20x-(4(6x+4)-3)-15=0



We calculate terms in parentheses: -(4(6x+4)-3), so:

4(6x+4)-3

We multiply parentheses

24x+16-3

We add all the numbers together, and all the variables

24x+13

Back to the equation:

-(24x+13)



We add all the numbers together, and all the variables

28x-(24x+13)-15=0

We get rid of parentheses

28x-24x-13-15=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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