2(y-3)=3(y-1)+7

Solution for 2(y-3)=3(y-1)+7 equation:

2(y-3)=3(y-1)+7

We move all terms to the left:

2(y-3)-(3(y-1)+7)=0

We multiply parentheses

2y-(3(y-1)+7)-6=0


We calculate terms in parentheses: -(3(y-1)+7), so:

3(y-1)+7

We multiply parentheses

3y-3+7

We add all the numbers together, and all the variables

3y+4

Back to the equation:

-(3y+4)


We get rid of parentheses

2y-3y-4-6=0

We add all the numbers together, and all the variables

-1y-10=0

We move all terms containing y to the left, all other terms to the right

-y=10

y=10/-1

y=-10