8x+42(1-x)=8+10x-6

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Solution for 8x+42(1-x)=8+10x-6 equation:



8x+42(1-x)=8+10x-6
We move all terms to the left:
8x+42(1-x)-(8+10x-6)=0
We add all the numbers together, and all the variables
8x+42(-1x+1)-(10x+2)=0
We multiply parentheses
8x-42x-(10x+2)+42=0
We get rid of parentheses
8x-42x-10x-2+42=0
We add all the numbers together, and all the variables
-44x+40=0
We move all terms containing x to the left, all other terms to the right
-44x=-40
x=-40/-44
x=10/11

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