23x-2=(5x+1)+(6x-7)+(3x-2)

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Solution for 23x-2=(5x+1)+(6x-7)+(3x-2) equation: 



23x-2=(5x+1)+(6x-7)+(3x-2)

We move all terms to the left:

23x-2-((5x+1)+(6x-7)+(3x-2))=0



We calculate terms in parentheses: -((5x+1)+(6x-7)+(3x-2)), so:

(5x+1)+(6x-7)+(3x-2)

We get rid of parentheses

5x+6x+3x+1-7-2

We add all the numbers together, and all the variables

14x-8

Back to the equation:

-(14x-8)



We get rid of parentheses

23x-14x+8-2=0

We add all the numbers together, and all the variables

9x+6=0

We move all terms containing x to the left, all other terms to the right

9x=-6

x=-6/9

x=-2/3

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